Motorola M500 Manuel d'utilisateur Page 27

  • Télécharger
  • Ajouter à mon manuel
  • Imprimer
  • Page
    / 32
  • Table des matières
  • MARQUE LIVRES
  • Noté. / 5. Basé sur avis des utilisateurs
Vue de la page 26
M500 180 Page 25
think it to be irrational not to play this game, once, for a trillion pounds.
However, if you were to advise others to be as rational, or thought this
a good enough reason to play again, or others thought the same way inde-
pendently, then terrible things could happen. It is as if the introduction of
the mean concept into assumptions based on the mode concept of expec-
tation make the reasonable expectations for a whole set of games less than
the sum of the reasonable expectation of any one game. This can’t be true
(any more than the outcome of a fair toss can depend upon prior tosses) so
perhaps (to propose a ‘solution’ similar to the one I proposed in the case
of the surprise exam paradox) it is not, after all, rational to play this game
for a trillion (monopoly) pounds.
Problem 180.6 Two pedestrians
Simon Rolph
Two pedestrians, P
1
and P
2
, are travelling at right angles to each other, but
are obscured by the corner of a building. Each is travelling parallel to the
wall nearest to them. Pedestrian P
i
is travelling at a constant speed of V
i
and the perpendicular distance between P
i
and the building is L
i
, i = 1, 2.
If the time they meet occurs at zero, find the time before impact at
which they can both see each other across the corner of the building.
Solution 176.5 Construct a square
Given a unit line segment, construct a unit square using com-
passes only.
Gordon Alabaster
Given unit line segment OA,
scribe a circle with centre O and
radius 1. With the compasses
set at 1, mark off from A to B,
from B to C and from C to D,
round the circle. By Pythago-
ras’ theorem, AC has length
3.
Set the compasses to
3. Scribe
arcs from A and from D to cross
at E. By Pythagoras’ theorem,
OE =
2.
A
B
C
D
E
F
G
O
Set the compasses to 1. Scribe arcs from E to intersect the circle with
centre O at F and G. Then the quadrilateral OFEG is a unit square since
OF = F E = EG = GO = 1 and OE =
2.
Vue de la page 26
1 2 ... 22 23 24 25 26 27 28 29 30 31 32

Commentaires sur ces manuels

Pas de commentaire